We have a random sample of n from the population. We can find the mean and standard deviation of the proportion of that sample that has the characteristic. X 1, X2, ..., Xn are n random variables that are independent and identically distributed with mean ? And standard deviation ?. Sn= X1+X2+...+Xn is the sample sum. We can show E (Sn)=n? And SD (Sn)=?
n. CLT states: Sn-n?
/0,1: as n
Question 3
Point estimates summarize the sample by a single number that is an estimate of the population parameter. An interval estimate is a range of values within which the true parameter lies with higher probability. In any estimation problem, we need to obtain both a point estimate and an interval estimate. The point estimate is our best guess of the true value of the parameter, while the interval estimate gives a measure of accuracy of that point estimate by providing an interval that contains plausible values.
To construct a confidence interval for a single unknown population mean ?, where the population standard deviation is known, we need x-as an estimate for ? And we need the margin of error. The margin of error is called the error bound for a population mean (EBM). The sample mean x? is the point estimate of the unknown population mean ?. The confidence interval estimate will have the form:(point estimate - error bound, point estimate + error bound) or, in symbols,(x?
EBM, x?+EBM) the margin of error depends...
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